Strategies
and Hints
-
Invert arrows 1 and 2, 2 and 3, 3 and 4, 4 and 5, or 5 and 6.
-
R(3, 4) followed by R(5, 6) results in
and then .
R(5, 6) followed by R(3, 4) results in and
then .
From this you can conclude that all different orderings of a given
set of moves are equivalent. Thus, an efficient solution will contain
no more than one occurrence of any action.
-
Since the final arrangement should look like ,
arrows 1 and 6 are already in the correct positions. It is reasonable
to conclude that R(1, 2) and R(5, 6) are not part
of the solution sequence.
Solution
Students
might also record solutions using the R(a, b) notation.

|