1.   Simplify
    A. 315 B.
    C. 15 D.
    Hint

  2.   Solve log6 ( y2 - 9) = log6 ( 7y - 21).
    A. 3, 4 B. -6, 4
    C. 4 D. 3, 6
    Hint

  3.   Find log 47.2 to four decimal places.
    A. 0.6739 B. 2.0791
    C. 1.6739 D. 3.8544
    Hint

  4.   Find log 136.8 to four decimal places.
    A. 2.1361 B. 2.1106
    C. 2.1418 D. 2.0502
    Hint

  5.   Find ln 6.21 to four decimal places.
    A. 1.8262 B. 497.7013
    C. 2.7183 D. 0.7931
    Hint

  6.   Find ln 0.732 to four decimal places.
    A. -0.5227 B. -0.4624
    C. -0.3120 D. -0.4719
    Hint

  7.   The number of bacteria in a culture grew exponentially. When the experiment began, there were 100,000. Ten minutes later, that number grew to 220,000. Which of the following equations could be used to model this situation?
    A. B.
    C. D.
    Hint

  8.   Solve log 3 x < 4. Check your solution.
    A. x < 64 B. x < 81
    C. 0 < x < 81 D. 0 < x < 64
    Hint

  9.   Use the fact that log 5 8 1.29 and log 5 10 1.43 to approximate the value of log 5 80.
    A. 1.11 B. 16
    C. 2.72 D. 1.84
    Hint

  10.   Solve the equation 2 log 6 x – log 6 5 = log 6 125.
    A. 25 B. –25
    C. 312.5 D. no solution
    Hint

  11.   Two cities have insect problems. The insects in City A increase exponentially according to the equation y = 120,000e0.04t. The insects in City B increase exponentially according to the equation y = 90,000e0.08t. In 15 years, which city will have more insects, and by approximately how much?
    A. City B, by about 80,000 B. City A, by about 30,000
    C. City B, by about 30,000 D. City A, by about 80,000
    Hint

  12.   Two cities have insect problems. The insects in City A increase exponentially according to the equation y = 120,000e0.04t. The insects in City B increase exponentially according to the equation y = 90,000e0.08t. When will the cities have an equal amount of insects?
    A. at t = 7.89 years B. at t = 7.19 years
    C. at t = 3 years D. at t = 34.66 years
    Hint



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