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1. |
A _________ is a line or segment that passes through the midpoint of a side of a triangle and is perpendicular to that side. |
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A. |
perpendicular bisector |
B. |
mode |
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C. |
median |
D. |
angle bisector |
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Hint |
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2. |
Which problem-solving strategy is used in indirect proofs? |
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A. |
draw a diagram |
B. |
guess and check |
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C. |
working backward |
D. |
decision-making |
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Hint |
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3. |
Refer to the figure. Is longer than Explain. |
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A. |
Yes; is the hypotenuse of and is a leg. |
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B. |
Yes; the shortest distance from a point to a line is a perpendicular segment. |
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C. |
All of these. |
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D. |
Yes; the measure of the angle opposite is 90 and the measure of the angle opposite must be less than 90 because the sum of the measures of the angles must be 180. |
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Hint |
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4. |
The _______________ states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side. |
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A. |
Definition of an Inequality |
B. |
Triangle Equality Theorem |
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C. |
Definition of a Triangle |
D. |
Triangle Inequality Theorem |
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Hint |
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5. |
Refer to the figure. Which statement is never true? |
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A. |
If DF = 20, FG = 13, and EG = 15, then EF = 11. |
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B. |
If is obtuse, then EG > EF. |
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C. |
If FG = 4, EGDE = 6, then EF < 18. |
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D. |
If EG = 6, ED = 8, and then FG = DF. |
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Hint |
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6. |
If 28 and 49 are the lengths of two sides of a triangle, between what two numbers must the measure of the third side fall? |
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A. |
10 and 60 |
B. |
28 and 49 |
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C. |
21 and 77 |
D. |
31 and 67 |
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Hint |
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7. |
In the figure, , , , and Write an inequality for the possible values of x. |
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A. |
x >  |
B. |
x >  |
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C. |
x >  |
D. |
x < -2 |
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Hint |
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8. |
Which statement can be proven using the SSS Inequality Theorem? |
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A. |
CD = AP |
B. |
m BAC < m PDA |
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C. |
m PDA < m BAC |
D. |
m B > m BCD |
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Hint |
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9. |
The __________ is the point of concurrency of the angle bisectors of a triangle. |
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A. |
centroid |
B. |
circumcenter |
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C. |
orthocenter |
D. |
incenter |
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Hint |
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10. |
State the assumption that could be used to start an indirect proof of the statement If 2n < 6, then n < 3. |
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A. |
n < 3 |
B. |
n = 3 |
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C. |
n 3 |
D. |
n > 3 |
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Hint |
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