| |
| |
1. |
To find the y-intercept of the graph of an equation, you should _______. |
| |
|
A. |
let x = 0 in the equation and solve for y |
B. |
multiply the coefficients of x and y |
| |
|
C. |
let x = –1 in the equation and solve for y |
D. |
let y = 0 in the equation and solve for x |
| |
|
Hint |
|
| |
2. |
Determine the x-intercept and y-intercept of the graph of the equation –3x + 5y = 15. |
| |
|
A. |
–5, –3 |
B. |
5, –3 |
| |
|
C. |
–5, 3 |
D. |
5, 3 |
| |
|
Hint |
|
| |
3. |
Determine the slope and y-intercept of the graph of –4 + 2y = 8x. |
| |
|
A. |
 |
| |
|
B. |
|
| |
|
C. |
m = 2; b = 4 |
| |
|
D. |
m = 4; b = 2 |
| |
|
Hint |
|
| |
4. |
To graph the equation by using the slope and y-intercept, you would ________. |
| |
|
A. |
graph the point at (–2, 0). Then go up 5 units and right 2 units. This will be the point at (0, 5). Then draw the line through points at (–2, 0) and (0, 5). |
| |
|
B. |
graph the point at (0, –2). Then go up 5 units and left 2 units. This will be the point at (–2, 3). Then draw the line through points at (0, –2) and (–2, 3). |
| |
|
C. |
graph the point at (0, –2). Then go up 5 units and right 2 units. This will be the point at (3, 2). Then draw the line through points at (0, –2) and (3, 2). |
| |
|
D. |
graph the point at (0, –2). Then go up 5 units and right 2 units. This will be the point at (2, 3). Then draw the line through points at (0, –2) and (2, 3). |
| |
|
Hint |
|
| |
5. |
Find the equation of the graph in slope-intercept form. |
| |
|
 |
| |
|
A. |
y = 2x + 3 |
B. |
y = 2x – 3 |
| |
|
C. |
y = 3x + 2 |
D. |
y = 3x – 2 |
| |
|
Hint |
|
|
|