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1. |
At their closest points, two planets are approximately 6.5 × 108 kilometers apart. Write the distance in standard form. |
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A. |
65,000,000 |
B. |
6,500,000 |
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C. |
650,000 |
D. |
650,000,000 |
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Hint |
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2. |
y = 2x is a(n)_____. |
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A. |
exponential function |
B. |
linear function |
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C. |
polynomial function |
D. |
power function |
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Hint |
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3. |
Given that log 5 = 0.6990, evaluate log 5000. |
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A. |
2.6990 |
B. |
5.6990 |
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C. |
3.6990 |
D. |
4.6990 |
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Hint |
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4. |
Evaluate . |
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A. |
4.2934 |
B. |
3.6444 |
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C. |
3.0893 |
D. |
3.5121 |
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Hint |
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5. |
Evaluate ln 5. |
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A. |
0.6690 |
B. |
1.7918 |
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C. |
1.6094 |
D. |
2.1312 |
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Hint |
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6. |
Solve Round to the nearest tenth. |
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A. |
37.2 |
B. |
284.9 |
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C. |
25.0 |
D. |
153.2 |
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Hint |
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7. |
Determine the amount of money in a money market account providing an annual rate of 6.5% compounded daily if the invested amount of $3,500 is left in the account for 5 years. |
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A. |
$3,735.03 |
B. |
$3,943.84 |
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C. |
$4,843.97 |
D. |
$1,343.97 |
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Hint |
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8. |
Find the balance of a $5,000 investment after 10 years earning 6.75% interest compounded continuously. |
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A. |
$10,033.86 |
B. |
$5,349.15 |
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C. |
$9,820.16 |
D. |
$5,033.86 |
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Hint |
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9. |
Compare the balance after 15 years of a $5,000 investment earning 7.12% interest compounded continuously to the same investment compounded semiannually. |
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A. |
You would earn $376.31 more by choosing the compounded continuously account. |
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B. |
You would earn $267.67 more by choosing the compounded continuously account. |
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C. |
You would earn $267.67 more by choosing the compounded annually account. |
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D. |
You would earn the same from both accounts. |
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Hint |
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10. |
Solve the equation  |
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A. |
50 |
B. |
5 |
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C. |
130 |
D. |
25 |
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Hint |
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11. |
Solve log4 x + log4 (x + 3) = log410. |
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A. |
5 |
B. |
-5 |
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C. |
2 |
D. |
-2 |
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Hint |
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12. |
Convert log4364 to a natural logarithm and evaluate. |
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A. |
4.2559 |
B. |
0.2351 |
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C. |
4.4889 |
D. |
4.2539 |
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Hint |
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13. |
If the population of a city can be modeled by the equation y = 12,500(1.03) x, where x is the number of years since 1965, what is the estimated population in 2006? |
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A. |
38, 611 |
B. |
41,999 |
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C. |
45,100 |
D. |
549,464 |
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Hint |
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14. |
The number of bacteria in a culture can be modeled by the exponential function N = 6.5828(1.1769)t, where t is the number of hours. What will the number of bacteria be in 19 hours? Round to nearest whole number. |
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A. |
121 |
B. |
203 |
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C. |
145 |
D. |
177 |
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Hint |
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