1.
Simplify
. Assume the denominator is not equal to zero.
A.
B.
C.
D.
Hint
2.
Arrange the terms of 6
x
4
y
2
– 4
x
2
y
+ 2
xy
3
+ 8 so that the powers of
y
are in ascending order.
A.
2
xy
3
+ 6
x
4
y
2
- 4
x
2
y
+ 8
B.
8 + 2
xy
3
- 4
x
2
y
+ 6
x
4
y
2
C.
6
x
4
y
2
- 4
x
2
y
+ 2
xy
3
+8
D.
8 – 4
x
2
y
+ 6
x
4
y
2
+ 2
xy
3
Hint
3.
Factor 54
x
3
y
2
A.
2
3
· 3 ·
x
·
x
·
x
·
y
·
y
B.
2 · 3
3
·
x
·
x
·
x
·
y
·
y
C.
2 · 3
3
·
x
·
x
·
y
·
y
·
y
D.
2 · 27 ·
x
·
x
·
x
·
y
·
y
Hint
4.
Suppose that the base of a triangle is 3
x
y
and its height is also 3
x
y
. What is its area, expressed as a monomial?
A.
x
4
B.
C.
6
x
2
y
2
D.
Hint
5.
Which expression is equivalent to ((3
2
)
4
)
3
?
A.
27
12
B.
9
9
C.
81
6
D.
9
6
Hint
6.
Simplify
.
A.
x
3
y
B.
x
2
y
2
C.
x
3
y
2
D.
x
2
y
Hint
7.
Which of the following expressions is an example of a polynomial with powers of
x
in ascending order?
A.
x
+ 2
x
3
– 2
x
2
– 5
x
4
B.
3
x
+ 5
x
3
– 7
x
4
– 3
C.
x
+ 2
x
3
+ 5
x
4
D.
x
+ 1 – 6
x
3
+ 2
x
4
Hint
8.
Find (4
x
2
– 2
x
– 3) + (–
x
2
+ 7
x
– 4).
A.
3
x
2
+ 5
x
– 7
B.
5
x
2
+ 5
x
– 7
C.
5
x
2
+ 5
x
+ 1
D.
3
x
2
+ 5
x
+ 1
Hint
9.
Anthony and Sanford each throw a football. The height of Anthony's throw can represented by the equation
A
= –10
x
2
+ 15
x
+ 22, where
A
is height and
x
is the time in seconds. The height of Sanford's throw can represented by the equation
S
= –9
x
2
+ 14
x
+ 23. At time
x
, what is the combined height of the throws?
A.
x
2
–
x
+ 1
B.
19
x
2
+ 29
x
+ 45
C.
–19
x
2
+ 29
x
+ 45
D.
–
x
2
+
x
– 1
Hint
10.
Multiply 4
x
2
(–
x
2
– 3
x
+ 2).
A.
–4
x
2
– 7
x
+ 8
B.
–4
x
2
– 12
x
+ 8
C.
–4
x
4
– 7
x
3
+ 8
x
2
D.
–4
x
4
– 12
x
3
+ 8
x
2
Hint
11.
Solve
x
(
x
– 2) + 2
x
(
x
+ 3) + 10 = 3
x
(
x
– 1) + 31.
A.
x
= 3
B.
x
= 2
C.
x
= –2
D.
x
= 4
Hint
12.
What is the GCF of 6
r
2
s
4
and 14
r
3
s
3
?
A.
B.
C.
D.
Hint
13.
Which sketch represents
A.
B.
C.
D.
Hint
14.
Which sketch represents
A.
B.
C.
D.
Hint