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1. |
Which graph represents the solution to x + 4 > -2? |
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A. |
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B. |
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C. |
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D. |
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Hint |
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2. |
Solve 3r + 5 > 26. |
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A. |
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B. |
r > 21 |
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C. |
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D. |
r > 7 |
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Hint |
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3. |
Use substitution to solve the system of equations given below.
y = 2x
5x - y = -24 |
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A. |
no solution |
B. |
(-8, -16) |
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C. |
(-4, -8) |
D. |
infinitely many solutions |
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Hint |
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4. |
Find a solution to the equation by doing the same thing to both sides.
3 – 6m = 5 – 7m |
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A. |
m = –2 |
B. |
m = –5 |
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C. |
m = 0 |
D. |
m = 2 |
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Hint |
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5. |
Find a solution to the equation by doing the same thing to both sides.
3(5f + 7) + 9(f + 4) = 9 |
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A. |
f = –9 |
B. |
f = –12 |
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C. |
f = –10 |
D. |
f = –2 |
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Hint |
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6. |
How could you use the graph of h = 20t – 6t2 to estimate the solution(s) of 20t – 6t2 = 7, where h stands for height and t stands for time? |
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A. |
Draw a horizontal line at h = 7 and find where it intersects the curve. |
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B. |
Draw a vertical line at t = 7 and find where it intersects the curve. |
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C. |
Draw a horizontal line at h = 20 and find where it intersects the curve. |
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D. |
Draw a vertical line at t = 20 and find where it intersects the curve. |
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Hint |
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7. |
A ball is launched straight up from ground level modeling the equation h = 52t – 10t2, where h stands for height in meters and t stands for time. On its way up, it reached a particular height at 1 second. On its way down, it again reached the same height. At approximately what time did it reach that height the second time? |
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A. |
4.2 seconds |
B. |
2.0 seconds |
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C. |
3.5 seconds |
D. |
5.2 seconds |
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Hint |
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8. |
Use a graph to solve the system of equations.
y = x2
y = –x + 2 |
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A. |
(–2, 4), (1, 1) |
B. |
(4, 1), (1, –2) |
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C. |
(–2, 1), (1, 4) |
D. |
(1, 1), (4, –2) |
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Hint |
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