1.
Solve 5
x
2
– 10
x
= 0.
A.
x
= 2
B.
x
= 0 or
x
= 2
C.
x
= 0 or
x
= -2
D.
x
= 0
Hint
2.
Solve
x
2
–
x
– 72 = 0.
A.
x
= 8 or
x
= -9
B.
x
= 9
C.
x
= -8
D.
x
= -8 or
x
= 9
Hint
3.
Solve the equation by backtracking.
A.
y
=
B.
y
= 3
C.
y
= 1
D.
y
=
Hint
4.
Solve the equation by backtracking.
A.
a
= 1
B.
a
= 10
C.
a
= -1
D.
a
= –10
Hint
5.
Find the solutions of the equation.3(
x
+ 1)
2
– 4 = 23
A.
x
= 2 and
x
= –4
B.
x
= 2 and
x
= –2
C.
x
= 4 and
x
= –4
D.
x
= 4 and
x
= –2
Hint
6.
Find the solutions of the equation.(
x
– 2)
2
– 1 = 3
A.
x
= 0 and
x
= –4
B.
x
= 4 and
x
= –4
C.
x
= –4 and
x
= –4
D.
x
= 0 and
x
= 4
Hint
7.
Solve the equation.6
x
2
– 12
x
+ 3 = 0
A.
x
= 0.29 and
x
= 1.71
B.
x
= –0.29 and
x
= 1.71
C.
x
= –0.29 and
x
= –1.71
D.
x
= 0.29 and
x
= –1.71
Hint
8.
Prospect High School decided to add a new parking lot for its increased student population. They just bought 15,000 ft
2
of land next to the school. The only requirement of the new parking lot is that the length should be 100 feet more than the width. Approximately what is the length and width of the parking lot?
A.
length: 184.17 ftwidth: 84.17 ft
B.
length: 300.03 ftwidth: 50.03 ft
C.
length: 180.56 ftwidth: 80.56 ft
D.
length: 182.29 ftwidth: 82.29 ft
Hint