1.
Solve the equation.
x
2
– 2
x
– 3 = 0
A.
x
= –5 and
x
= 0
B.
x
= 5 and
x
= 0
C.
x
= 3 and
x
= –1
D.
x
= 2 and
x
= –1
Hint
2.
Solve the equation.6
x
2
– 12
x
+ 3 = 0
A.
x
= 0.29 and
x
= –1.71
B.
x
= –0.29 and
x
= 1.71
C.
x
= 0.29 and
x
= 1.71
D.
x
= –0.29 and
x
= –1.71
Hint
3.
Prospect High School decided to add a new parking lot for its increased student population. They just bought 15,000 ft
2
of land next to the school. The only requirement of the new parking lot is that the length should be 100 feet more than the width. Approximately what is the length and width of the parking lot?
A.
length: 182.29 ftwidth: 82.29 ft
B.
length: 180.56 ftwidth: 80.56 ft
C.
length: 184.17 ftwidth: 84.17 ft
D.
length: 300.03 ftwidth: 50.03 ft
Hint
4.
Find the quadratic equation with 0 solutions.
A.
x
2
– 2
x
+ 5 = 0
B.
x
2
– 12
x
+ 36 = 0
C.
x
2
– 2
x
– 3 = 0
D.
x
2
+ 4
x
– 12 = 0
Hint
5.
Find the quadratic equation with 1 solution.
A.
x
2
– 10
x
+ 21= 0
B.
x
2
– 2
x
+ 2= 0
C.
x
2
+ 6
x
+ 9 = 0
D.
4
x
2
+ 4
x
– 35= 0
Hint