Teachers Notes:
Characterizing a hydrocarbon

Problem 1:
a. C₃H₈ → C₃H₆ + H₂
→ + H-H

b. C₇H₁₆ → C₃H₈ + C₄H₈

→ +

c. C₁₀H₂₂ → C₅H₁₂ + C₅H₁₀

→ +

Problem 2:
1. Location of the double bond is one possible isomer. These could include 1-dodecene, 2-dodecene, 3-dodecene, 4-dodecene, 5-dodecene, and 6-dodecene.

          
(Hydrogen omitted to simplify the drawing)

2. Branched compounds are a second type of isomer.

3,4 dimethyl, 2-decene       

3. Geometric isomers include attached groups on the carbons the double bond.

3,4 diethyl-3-octene (trans)       

3,4 diethyl-3-octene (cis)          

or trans-6-dodecene and cis-6-dodecene